Memory Probability Tree

../_images/memory.jpg

Goal

Students calculate how many turns a game of memory will take.

Lesson Plan

1. Cooperative Memory

Play a cooperative game of Memory: Place all cards face-down on a table. Players take turns and unveil a pair of cards. If the cards match, the pair is removed and they get to unveil another pair. If the cards mismatch, it’s the next players turn.

Players may give each other hints. Count how many turns you need in total.

Hint

With 20 pairs the game takes should take about 5 minutes. With 36 pairs about 15.

2. Perfect Matches

Calculate together, what is the probability to unveil all pairs in one turn. Of course, that depends on the number of pairs. E.g. for 20 cards you get:

\[p(perfect) = \frac{1}{19} \cdot \frac{1}{17} \cdot \frac{1}{15} ...\]

3. Game situations

Now, analyze a game with three pairs. For a full analysis, you will need to draw a probability_tree covering all possible game situations.

Give pairs of students a deck of three memory cards each. Ask them to write down all situations that could occur.

Hint

There are nine possible situations. We will abbreviate them:

  • 6:0 – six cards, no cards seen

  • 2:1 – two cards left, one card seen

  • 4:3x – four cards left, three seen and a pair was among them

4. Tree

Construct a tree by analyzing which situation can follow from which. Draw the tree without probabilities first. There should be 7 paths.

At the bottom of each path, write the number of turns.

The result could look like this:

../_images/memory_tree.jpg

probability tree for memory with 6 cards (including a small bug)

5. Transition Probabilities

Annotate the tree with probabilities for going from one node to the next. Although many nodes have only one possibility, this needs an entire board. The nodes have up to three possible transitions. The complete set of transitions looks like this:

start

transition 1

transition 2

transition 3

6:0

p(4:0) = 1/5

p(6:2) = 4/5

6:2

p(4:2) = 1/3

p(4:1) = 1/2

p(6:4x) = 1/6

6:4x

p(4:2) = 1/1

4:0

p(2:0) = 1/3

p(4:2) = 2/3

4:1

p(2:0) = 1/3

p(2:1) = 1/2

p(4:3x) = 1/6

4:2

p(4:1) = 1/1

4:3x

p(2:1) = 1/1

2:0

p(0:0) = 1/1

2:1

p(0:0) = 1/1

Read the table like this:

  • if there are 6 cards left and I have seen none of them (6:0), there is a 20% chance that I will find a pair and move to state (4:0)

  • if there are 4 cards left and I have already seen 2 cards with different pictures (4:2), there is a 2/3 chance that I won’t find any pair and therefore move to (4:2).

6. Path Probabilities

Calculate the probability for each path by multiplying the transition probabilities. This is a good opportunity to introduce joint probabilities.

7. Check

Make sure the probabilities add up to 1.0. This is a good opportunity to introduce total probatility.

8. Simulate

By now, it should have become clear that drawing a complete probability tree even for 6 cards is a lot of work. How would you ever finish calculating probabilities for a bigger game?

A pragmatic approach is to simulate the game many times with a computer. Run the simulation through the Memory Simulation and see whether you get the same probabilities.